Marksheme

C1 Revision Questions Sheet 1 1.(a)9B11 (b)[pic] = 333 = 27M1 A12 (c)[pic]B1 ft1 [4] 2.(a)3?5 (or a = 3)B11 (b)[pic]M1 (3 ?5)(3 + ?5) = 9 5 (= 4) (Used as or intended as denominator)B1 (3 + ?5)(p ± q ?5) = ... 4 ground (p ? 0, q ? 0) (Independent)M1 or (6 + ?5)(p ± q?5) = ... 4 terms (p ? 0, q ? 0) [Correct version: (3 + ?5)(3 + ?5) = 9 + 3?5 + 3?5 + 5,or double this.] [pic] = 7 + 3?5 1st A1: b = 7, 2nd A1: c = 3A1 A15 [6] 2nd M mark for attempting (3 + ?5)(p + q ?5) is generous. Condone errors. 3.(a)y = 8 ? 2x3x2 + x(8 ? 2x) = 1M1 x2 + 8x ? 1 = 0(*)A12 (b)x = [pic] = ?4 ±M1 A1 [pic] = 2[pic]; x = 4 + 2[pic] or x = 4 2[pic]B1 y = 8 ? 2(?4 + [pic]) = 16 ? 2[pic] or y = 16 + 2[ pic]M1 A15 [7] 4.

(a)4x(x + 3) = 0, x = (or use of quadratic formula)M1 x = 0 x = 3A1 A13 (b)Using b2 4ac = 0 or other manner, proceed to c = M1 c = 9A1 (2x + 3)(2x + 3) = 0 x = (or other method to conclude a 3-term quadratic)M1 x = [pic]A14 [7] C1 Revision Questions Sheet 2 1.Rationalising every surdM1 [pic]A1, A1 ??6 + 2?3 + ?2(or p = ?1, q = 2, r = 1)A14 [4] 2.(a)b2 4ac = (k)2 36 = k2 36M1 A1 Or, (completing the square), [pic] Or, if b2 and 4ac are compared directly, [M1] for finding both [A1] for k2 and 36.M1 A1 No real soluti! ons: k2 36 < 0, 6 < k < 6 (ft their 36)M1, A1ft4 (b)x2 4x + 9 = (x 2)2 . (p = 2)B1 skip statement p = ?2 if differently correct. x2 4x + 9 = (x 2)2 4 +9 = (x 2)2 + 5 (q = 5)M1 A13 M: Attempting (x ± a)2 ± b ± 9, a ? 0, b ? 0. (c)Min value...If you want to get a full essay, order it on our website: OrderEssay.net

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