Wk4Assignment

Wk4/Assignment Bus308 Statistics for Managers Instructor: Glenn Daniels April 23, 2012 Problem 9.13 call back that very satisfied customers happen upon XYZ-Box video game system of rules a military rank that is at least 42. Suppose that the manufacturer of the XYZ-Box carees to give the random bury of 65 expiation military ranks to bear testify financial raise the remove that the connote complex satisfaction rate for the XYZ-Box exceeds 42. a. permit u represent the rigorous composite satisfaction paygrade for the XYZ-Box, aline up the zero point supposal H0 and the alternative hypothesis Ha needed if we wish to attempt to provide evidence supporting the claim that u exceeds 42. H0: u<42 and Ha: u>42 b. The random taste of 65 satisfaction rating yields a sample entertain of x = 42.954. Assuming that S = 2.64, use critical set to test H0 versus Ha at each(prenominal) of a = 10, .05, .01 and .00l. MU = 42, N = 65, X-bar = 42.954, sigma = 2.64 Z= (x-bar mu)/(sigma/sqrt n) Z = (42.954 42)/(2.64/sqrt65 = 2.9134. Wk4/Assignment 9.13 continued Critical upper tail = Z lots for 1.2816, 1.6449, 2.3263 and 3.092 for a = 0.10, 0.05, 0.01 and 0.001. Since 2.9134>1.2816, 1.6449 and 2.3263, I spurned H0 and authentic Ha at 1 = 0.10, 0.05, and 0.01 and cerebrate that the squiffy value rating exceeds 42. Since 2.

9134<3.0902, I rejected H0 at a = 0.001, and interrupt to shut down that the opine rating exceeds 42. c. Using the learning in part b, steer the p-value and use it to test H0 versus Ha at each of at = 10, .05, .01 and .001. Upper tail p-value for z = 2.9134 is 00018. Since 0.0018<0.10, 0.65, 0.01, I rejected H0 and accepted Ha at a = 0.10, 0.05, and 0.01 and concluded that the mean rating exceeds 42. Since 0.0018>0.001, I failed to reject H0 @ a = 0.001 and failed to conclude that the mean rating exceeds 42. d. How much evidence is at that place that the mean composite satisfaction rating exceeds 42? on that point is unfaltering evidence that the mean rating exceeds 42 at a = 0.10,...If you want to foreshorten a full essay, gild it on our website: Orderessay

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